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Table 3 Association between TyG and non-cardiovascular mortality

From: The association between TyG and all-cause/non-cardiovascular mortality in general patients with type 2 diabetes mellitus is modified by age: results from the cohort study of NHANES 1999–2018

 

Hazard ratio (95% confidence interval)

Model 1

Model 2

Model 3

Model 4

TyG (continuous)

P for interaction < 0.001

P for interaction < 0.001

P for interaction < 0.001

P for interaction < 0.001

 Total

0.98 (0.86–1.11)

1.09 (0.95–1.25)

1.09 (0.95–1.25)

1.05 (0.90–1.22)

 < 65 yrs

1.55 (1.25–1.94)*

P < 0.001

1.59 (1.27-2.00)*

P < 0.001

1.60 (1.28-2.00)*

P < 0.001

1.54 (1.18–2.01)*

P < 0.002

 ≥ 65 yrs

0.85 (0.72–1.01)

0.90 (0.76–1.06)

0.91 (0.77–1.08)

0.92 (0.76–1.12)

TyG (categorical)

P for interaction = 0.002

P for interaction = 0.002

P for interaction < 0.001

P for interaction = 0.001

  TyG tertile 1

Reference

Reference

Reference

Reference

 Total

    

  TyG tertile 2

0.79 (0.64–0.98)*

P = 0.032

0.81 (0.65–0.99)*

P = 0.045

0.87 (0.70–1.07)

0.84 (0.68–1.05)

  TyG tertile 3

0.92 (0.75–1.12)

1.06 (0.87–1.30)

1.07 (0.87–1.32)

1.01 (0.81–1.27)

 < 65 yrs

    

  TyG tertile 2

0.94 (0.61–1.43)

0.89 (0.58–1.36)

0.98 (0.63–1.51)

0.93 (0.60–1.45)

  TyG tertile 3

1.55 (1.07–2.24)*

P = 0.020

1.54 (1.07–2.24)*

P = 0.021

1.64 (1.12–2.41)*

P = 0.011

1.44 (1.01–2.18)*

P = 0.048

 ≥ 65 yrs

    

  TyG tertile 2

0.72 (0.56–0.92)*

P = 0.008

0.82 (0.64–1.04)

0.87 (0.68–1.12)

0.87 (0.67–1.12)

  TyG tertile 3

0.82 (0.64–1.05)

0.90 (0.70–1.15)

0.92 (0.71–1.18)

0.94 (0.71–1.34)

  1. Model 1 was unadjusted
  2. Model 2 was adjusted for age and gender
  3. Model 3 was adjusted for age, gender, ethnicity, educational level, BMI, CHF, albumin, eGFR, UACR, insulin treatment, and metformin
  4. Model 4 was adjusted for age, gender, ethnicity, educational level, current smoking, BMI, CHF, CAD, hypertension, albumin, LDL-C, eGFR, HbA1c, UACR, UA, Insulin treatment, metformin, and statins
  5. *indicated that the p value was less than 0.05