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Table 2 Association between TyG and all-cause mortality

From: The association between TyG and all-cause/non-cardiovascular mortality in general patients with type 2 diabetes mellitus is modified by age: results from the cohort study of NHANES 1999–2018

 

Hazard ratio (95% confidence interval)

Model 1

Model 2

Model 3

Model 4

TyG (continuous)

P for interaction < 0.001

P for interaction < 0.001

P for interaction < 0.001

P for interaction < 0.001

 Total

0.98 (0.88–1.09)

1.10 (0.98–1.23)

1.11 (0.99–1.25)

1.00 (0.88–1.14)

 < 65 yrs

1.47 (1.22–1.76)*

P < 0.001

1.50 (1.24–1.81)*

P < 0.001

1.48 (1.23–1.79)*

P < 0.001

1.33 (1.06–1.66)*

P = 0.014

 ≥ 65 yrs

0.89 (0.77–1.02)

0.94 (0.81–1.08)

0.98 (0.85–1.13)

0.91 (0.78–1.12)

TyG (categorical)

P for interaction < 0.001

P for interaction < 0.001

P for interaction < 0.001

P for interaction < 0.001

  TyG tertile 1

Reference

Reference

Reference

Reference

 Total

    

  TyG tertile 2

0.79 (0.66–0.94)*

P = 0.008

0.80 (0.67–0.96)*

P = 0.014

0.89 (0.74–1.06)

0.83 (0.69–0.99)*

P = 0.043

  TyG tertile 3

0.92 (0.78–1.08)

1.06 (0.90–1.26)

1.12 (0.94–1.33)

0.96 (0.79–1.16)

 < 65 yrs

    

  TyG tertile 2

0.96 (0.67–1.38)

0.92 (0.64–1.31)

1.02 (0.71–1.47)

0.97 (0.67–1.40)

  TyG tertile 3

1.57 (1.15–2.14)*

P = 0.005

1.56 (1.14–2.14)*

P = 0.005

1.66 (1.20–2.30)*

P = 0.002

1.40 (1.03–1.99)*

P = 0.046

 ≥ 65 yrs

    

  TyG tertile 2

0.71 (0.58–0.87)*

P < 0.001

0.81 (0.66–0.99)*

P < 0.043

0.90 (0.73–1.10)

0.84 (0.68–1.04)

  TyG tertile 3

0.83 (0.67–1.01)

0.90 (0.74–1.11)

0.96 (0.78–1.19)

0.87 (0.69–1.09)

  1. Model 1 was unadjusted
  2. Model 2 was adjusted for age and gender
  3. Model 3 was adjusted for age, gender, ethnicity, BMI, CHF, CAD, albumin, LDL-C, eGFR, UACR, Insulin treatment, and metformin
  4. Model 4 was adjusted for age, gender, ethnicity, educational level, current smoking, BMI, CHF, CAD, hypertension, albumin, LDL-C, eGFR, HbA1c, UACR, UA, Insulin treatment, metformin, and statins
  5. *indicated that the p value was less than 0.05